Problem of the Month (April 2008)
Given a polyomino P and a positive integer n ≥ 2, what is the largest possible shape S so that n congruent non-overlapping copies of S can be packed inside P? (If P is a rectangle, or if n is a multiple of the area of P, then this problem is too easy, so we restrict our attention to the other cases.) Can you improve any of the results below? What about other polyforms? What about other shapes?
ANSWERS
The following people sent in best-known solutions this month: Károly Hajba, Andrew Bayly, Joe DeVincentis, George Sicherman, Gabriele Carelli, Livio Zucca, Jeremy Galvagni, Maurizio Morandi, and Gavin Theobald. I recently heard from Dick Hess, Yoshiyuki Kotani, and Robert Wainwright that they had considered this problem a decade ago. There was much improving upon other's ideas, so all these folks deserve credit.
Here are the best known non-trivial solutions:
Triomino In 4 Parts
| 1
|
|
|
Triomino In 5 Parts
Triomino In 7 Parts
Triomino In 10 Parts
| 1
|  (Joe DeVincentis)
|
|
Triomino In 11 Parts
Triomino In 13 Parts
Triomino In 14 Parts
| 1
|  (Joe DeVincentis)
|
|
Triomino In 16 Parts
| 1
|
|
|
Triomino In 17 Parts
Triomino In 19 Parts
| 95⁄96
|
|
|
Triomino In 20 Parts
| 1
|  (Joe DeVincentis)
|
|
Tetrominoes In 3 Parts
| 15⁄16
|
|
|
Tetrominoes In 5 Parts
Tetrominoes In 6 Parts
Tetrominoes In 7 Parts
Tetrominoes In 9 Parts
| 1
|
|
|
Tetrominoes In 10 Parts
Tetrominoes In 11 Parts
Tetrominoes In 13 Parts
Tetrominoes In 14 Parts
Pentominoes In 2 Parts
| 9⁄10
|  (Dick Hess)
|  (Dick Hess)
|
|
Pentominoes In 3 Parts
| 1
|  (Dick Hess)
|
| 1–ε
|  (Andrew Bayly)
|
| 15⁄16
|  (Dick Hess)
|  (Dick Hess)
|  (Dick Hess)
|
| 9⁄10
|  (Dick Hess)
|  (Dick Hess)
|  (Dick Hess)
|  (Dick Hess)
|
|
Pentominoes In 4 Parts
| 9⁄10
|  (Dick Hess)
|  (Dick Hess)
|
|
Pentominoes In 6 Parts
| 1
|  (Dick Hess)
|  (Dick Hess)
|  (Dick Hess)
|
| 1–ε
|  (Livio Zucca)
|
| 24⁄25
|  (Dick Hess)
|  (Livio Zucca)
|
|
Pentominoes In 7 Parts
Pentominoes In 8 Parts
| 1
|  (Erich Friedman)
|
| 19⁄20
|  (Joe DeVincentis)
|
(most by Maurizio Morandi)
|
Pentominoes In 9 Parts
| 1
|  (Livio Zucca)
|
| 153⁄160
|  (Joe DeVincentis)
|
|
Pentominoes In 11 Parts
| 44⁄45
|  (Joe DeVincentis)
|  (Joe DeVincentis)
|  (Joe DeVincentis)
|  (Joe DeVincentis)
|
 (Joe DeVincentis)
|  (Joe DeVincentis)
|  (Joe DeVincentis)
|  (Joe DeVincentis)
|
|
Pentominoes In 12 Parts
| 1
|  (Joe DeVincentis)
|  (Joe DeVincentis)
|  (Joe DeVincentis)
|  (Joe DeVincentis)
|
 (Joe DeVincentis)
|  (Joe DeVincentis)
|  (Joe DeVincentis)
|  (Joe DeVincentis)
|
|
Hexominoes In 2 Parts
| 1–ε
|  (Andrew Bayly)
|  (Andrew Bayly)
|  (Gavin Theobald)
|  (Gavin Theobald)
|
|
Hexominoes In 3 Parts
| 1–ε
|  (Andrew Bayly)
|  (Andrew Bayly)
|  (Andrew Bayly)
|  (Andrew Bayly)
|
| 11⁄12
|  (Maurizio Morandi)
|
| 5⁄6
|
|
|
| 5⁄6–ε
|  (George Sicherman)
|
|
Hexominoes In 4 Parts
| 1–ε
|  (Andrew Bayly)
|
| 11⁄12
|  (Livio Zucca)
|
| 5⁄6
|
|
|
Hexominoes In 5 Parts
| .9725+
|  (Maurizio Morandi)
| (Enlarge)
|
| 35⁄36
|
|
|
| 25⁄27
|
|
|
|  (Gavin Theobald)
|  (Gavin Theobald)
|
| 175⁄192
|  (Gavin Theobald)
|
| 65⁄72
|  (Gavin Theobald)
|  (Gavin Theobald)
|
| 85⁄96
|
|
|
Triangle in 5 Parts
| 5(21√3-34)/12 = .988+
|  (Maurizio Morandi)
| (Enlarge)
|
|
Triangle in 7 Parts
Triangle in 10 Parts
| 5(48√3 - 35)/242 = .994+
|  (Maurizio Morandi)
| (Enlarge)
|
|
Triamond in 5 Parts
| 5(21√3 - 34)/12 = .988+
|  (Maurizio Morandi)
| (Enlarge)
|
|
Triamond in 7 Parts
| 7(32√3 - 55)/3 = .993+
|  (Maurizio Morandi)
| (Enlarge)
|
|
Triamond in 8 Parts
| 1
|  (Maurizio Morandi)
|
|
Pentiamonds in 2 Parts
| 14⁄15
|  (George Sicherman)
|
|
Pentiamonds in 3 Parts
| 1
|  (Maurizio Morandi)
|
| 14⁄15
|  (Maurizio Morandi)
|
| 9⁄10
|  (George Sicherman)
|
|
Pentiamonds in 4 Parts
| 1
|  (George Sicherman)
|
| 19⁄20
|  (Joe DeVincentis)
|
|
Pentiamonds in 6 Parts
| 1
|  (George Sicherman)
|
| 591⁄610
|  (Maurizio Morandi)
| (Enlarge)
|
|
Pentiamonds in 7 Parts
| 279⁄280
|  (Maurizio Morandi)
| (Enlarge)
|
| 14⁄15
|  (George Sicherman)
|
|
Pentiamonds in 8 Parts
| 1
|  (George Sicherman)
|
|
Hexiamonds in 2 Parts
| 1–ε
|  (George Sicherman)
|
|
Hexiamonds in 3 Parts
| 1–ε
|  (George Sicherman)
|  (Andrew Bayly)
|
|
Hexiamonds in 4 Parts
Hexiamonds in 5 Parts
| 14⁄15
|  (Maurizio Morandi)
|
| 25⁄27
|  (George Sicherman)
|
|
Hexiamonds in 7 Parts
| 14⁄15
|
|
| (most by Maurizio Morandi)
|
|
Heptiamonds in 2 Parts
| 20⁄21
|
|
|
| 6⁄7–ε
|  (all by George Sicherman)
|
|
Heptiamonds in 3 Parts
| 1
|  (George Sicherman)
|  (George Sicherman)
|
|
|
| 41⁄42
|
|
| 20⁄21
|
|
|
| 6⁄7
|  (George Sicherman)
|  (George Sicherman)
|  (George Sicherman)
|  (George Sicherman)
|
| (most by Maurizio Morandi)
|
|
Heptiamonds in 4 Parts
| 1
|  (George Sicherman)
|
| 27⁄28
|
|
| 20⁄21
|  (George Sicherman)
|  (George Sicherman)
|
| 19⁄21
|
|
| 6⁄7
|  (George Sicherman)
|
| (most by Maurizio Morandi)
|
|
Heptiamonds in 5 Parts
| 1
|
|
| 25⁄28
|  (George Sicherman)
|
| (most by Maurizio Morandi)
|
|
Heptiamonds in 6 Parts
| 1
|  (George Sicherman)
|
| 41⁄42
|  (Joe DeVincentis)
|  (Joe DeVincentis)
|
| (most by Maurizio Morandi)
|
|
Heptiamonds in 8 Parts
| 1
|  (George Sicherman)
|
| 20⁄21
|
|
| 13⁄14
|
|
| (most by Maurizio Morandi)
|
|
After Joe DeVincentis showed that (1-ε) of a particular hexomino could be covered by 3 pieces, Andrew Bayly proved that at least (1-ε) of any step polyomino could be covered by any number of pieces in this manner. His "proof by picture":

If you can extend any of these results, please
e-mail me.
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